[Kent Geisler]

It was the solution I chose

[Kent Geisler]

Jim,

We are running 5.7P

Below the test-schema I am using (also attached) where the type of the datotid-field is “dateTime”.

It’s right, if I change the type of datotid to: ENGINE=”s.string” it runs without errors.

<s:schema xmlns:s="http://www.w3.org/2001/XMLSchema”&gt;

 

   

     

       

     

   

 

If I make a HL7-variant where the type of MSH.7 is changed from TS to ST it also runs without errors.

[Kent Geisler]

Jim,

Below my tries and the results:

First try with no input except the hardcoded datetime

prologue

   type: xlt

   version: 7.0

end_prologue

{ { OP COPY }

   { ERR 0 }

   { PRE {

       set out “2011-09-08T16:47:00”

       set xlateOutVals $out

   }}

   { IN {} }

   { OUT testDatoTid.datotid.#text }

}

Result in TestTool where I can parse the date to the xml-field:

Command output:

MESSAGE 1

testDatoTid.datotid.#text:   >2011-09-08T16:47:00<

Second try with MSH-7 as input field, but not used:

prologue

   type: xlt

   version: 7.0

end_prologue

{ { OP COPY }

   { ERR 0 }

   { PRE {

       set out “2011-09-08T16:47:00”

       set xlateOutVals $out

   }}

   { IN {{0(0).MSH(0).#7(0).[0]}} }

   { OUT testDatoTid.datotid.#text }

}

Result in TestTool where I get the error:

MESSAGE 1

[0:TEST] Warning: The format of source value ‘2011-09-08T16:47:00’ is inconsistent with its type: ‘ts’

[0:TEST] Message encode warnings: Error generated during parsing. – Element ‘datotid’ got Datatype error, Type:SchemaDateTimeException, Message:buffer not initialized yet!. – Line 1, Col 130

Output validation errors: Error generated during parsing. – Element ‘datotid’ got Datatype error, Type:SchemaDateTimeException, Message:buffer not initialized yet!. – Line 1, Col 130

[0:TEST] Error generated during parsing. – Element ‘datotid’ got Datatype error, Type:SchemaDateTimeException, Message:buffer not initialized yet!. – Line 1, Col 172

[Kent Geisler]

Jim and Levy,

Below is my tcl and xlate

I have previously tried to display the datetime returned from the xlate, and it has the right value.

I have considered making a HL7 variant and change the data type from TS to ST. Maybe it’s the easiest way to solve the problem.

######################################################################

# Name: xlt_convert_tid

# Purpose: Transform timestamps

# UPoC type: xltp

# Args: input_timestamp

# input_format

# output_format

# Return: output_timestamp

#

proc xlt_convert_tid {} {

upvar xlateId xlateId

xlateInList   xlateInList

xlateInTypes  xlateInTypes

xlateInVals   xlateInVals

xlateOutList  xlateOutList

xlateOutTypes xlateOutTypes  

xlateOutVals  xlateOutVals

set tid  [ lindex $xlateInVals 0 ]

set in_fmt  [ lindex $xlateInVals 1 ]

set out_fmt  [ lindex $xlateInVals 2 ]

set cen “”

set year “”

set mon “”

set day “”

set hour “00”

set min “00”

set sec “00”

set sec1 “0”

if { $in_fmt == “YYMMDD” } {

set year [string range $tid 0 1 ]

set mon [string range $tid 2 3 ]

set day [string range $tid 4 5]

# Fjern foranstillet 0, s

[Author]

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