Regular Expression Help

[Keith McLeod]

I need to replace either pattern in OBX:5.  Since this comes from different/many labs systems, I need it to work on either possibility.

search for E.brE or .br and replace each occurence with ~.

The .br expression works fairly easily but not having much luck on the E.brE expression.

Topic

[David Barr]

The patterns should be \E\.br\E\ and \.br\, but you can use (\E\.br\E\|\.br\) to match either one.

If someone is sending you E.brE then they are doing something wrong.

[Keith McLeod]

I would believe that what you sent would work, but this is what I get when actually using it.

regsub -all {(\E\.br\E\|\.br\)} $xlateInVals {~} xlateOutVals

E~E for the one with E contained in it, but works on the .br as you can see it replaced that pattern in the middle of the string.

If I remove the |\.br\

[David Barr]

You should probably replace $xlateInVals with [lindex $xlateInVals 0] seeing as how it’s a list being passed to a command that expects a string. I’m not sure if that’s the cause of the problem. Have you tried echoing out $xlateInVals to see what it looks like?

[Keith McLeod]

Tried both of those.  No luck on it as of yet.

[Charlie Bursell]

I would try string map

First map all instances of .br to ~ and then all instances of E to “”

To make sure of the order do like

set inp [string map

[lindex $xlateInVals 0]]

set xlateOutVals

]

[Keith McLeod]

Here is what I ended up with so far until I can break it.

regsub -all {([\]+E[\]+.br[\]+E[\]+|\.br\)} [lindex $xlateInVals 0] {~} obx_5

set xlateOutVals

I may try Charlies as well and see how that goes…

[Author]

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