How to CONCAT all OBX.5 into a single OBX?

Typically the receiving system wants the elements from each OBX-5 to be as repeating OBX-5 field in one OBX (not concatenated together).

Are you sure that is not what is needed?

For example:

ib:

OBX|01|TX|Abdomen 1V^Abdomen 1v^Rad|01|1016180 Oloughlin Kathleen|…

OBX|02|TX|Abdomen 1V^Abdomen 1v^Rad|01||…

OBX|03|TX|Abdomen 1V^Abdomen 1v^Rad|01|Screening Mammogram:||…

ob:

OBX|01|TX|Abdomen 1V^Abdomen 1v^Rad|01|1016180 Oloughlin Kathleen~~Screening Mammogram:~…

Using your example.

Rather than an ob:

OBX|01|TX|Abdomen 1V^Abdomen 1v^Rad|01|1016180 Oloughlin KathleenScreening Mammogram:…

THe technique for either is similar but yet different – and you want to get correct what the receiving system wants.

Jim Kosloskey

Sorry, for some reason I missed your sample OUTPUT.

OK –

Iterate through the OBX (probably a group) and concat the OBX-5 value with a temp variable and the .br.

When the iteration is finished the temp variable will have the concatenated information with an additional .br. You can either leave it as it may not cause a problem or remove it using a Tcl proc.

Then copy the temp variable to the first (and only) ob OBX-5. Of cpourse you can either copy the rest of the OBX from the first IB OBX-5 before the iterate or after.

Jim Kosloskey

My guess is your basis is incorrect.

One way to check it is to run the HL/7 Tester using the IB variant and the message with which you are testing. Turn the noise level on the Tester to 2 and observe where the address path changes for each OBX.

I think you will see it change at 1(0).1(0).1(0) not 1(0).1(0).1(0).OBX.

So I think this is a group iteration not a segment iteration (usually is group). If it is your Source: would be 1(0).1(0).1(%g1).OBX(0).00573  

Anyway, run the HL/7 tester and make sure.

Jim Kosloskey